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निम्नलिखित सम्मिश्र संख्याओं को ध्रुवीय रूप में लिखे । (i) `sin30^(@)+icos30^(@)` (ii) `1+i` (iii) `-4+i4sqrt(3)` (iv) `((2+i)/(3-i))^(2)` (v) `(-16)/(1+isqrt(3))` (vi) `(i-1)/("cos"(pi)/(3)+i "sin"(pi)/(3))` (vii) `(i-sqrt(3))^(13)` (viii) `-1-isqrt(3)` (ix) `(-1-sqrt(2)i)` (x) `3-4i` |
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Answer» Correct Answer - (i) `"cos"(pi)/(3)+i"sin"(pi)/(3)` (ii) `sqrt(2)("cos"(pi)/(4)+i "sin"(pi)/(4))` (iii) `8("cos"(2pi)/(3)+i "sin"(2pi)/(3))` (iv) `(1)/(2)("cos"(pi)/(2)+i "sin"(pi)/(2))` (v) `8("cos"(2pi)/(3)+i "sin"(2pi)/(3))` (vi) `sqrt(2)("cos"(5pi)/(12)+i "sin"(5pi)/(12))` (vii) `8192(cos 150^(@)+i sin150^(@))` (viii) `2(cos240^(@)+isin240^(@))` (ix) `sqrt(3)(costheta+isintheta),theta=tan^(-1)sqrt(2)` (x) `5(costheta-isintheta)` (xi) `sqrt(2)("cos"(pi)/(4)-i"sin"(pi)/(4))` (ii) `+i=r(costheta+isintheta)rArrrcostheta=1,rsintheta=1` `rArr" "tantheta=1,theta=(pi)/(4)` तथा `r=sqrt(2)` `:.` ध्रुवीय रूप `=sqrt(2)("cos"(pi)/(4)+i "sin"(pi)/(4))` |
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