1.

Niobium crystallises in body-centred cubic structure. If density is 8.55 g cm^(3), calculate atomic radius of niobium using its atomic mass of 93 u.

Answer»

Solution :The equation CONNECTING these quantities is given by
`a^(3)=(Mxxz)/(dxxN_(A))`,
Substituting the values, we get
`a^(3)=(93xx2)/(8.55xx6.022xx10^(23)) or a=330.4xx10^(-10)cm or a=330.4" PM"`
For body - centred cubic, `r=(SQRT3)/(4)a=0.433xx330.4=143.1" pm."`


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