1.

Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide : 2NO(g)+O_(2)(g)to2NO_(2)(g) What is the predicated rate law if the mechanism is {:(NO(g)+O_(2)(g)hArrNO_(3)(g),,("fast")),(NO_(3)(g)+NO(g)to2NO_(2)(g),,("slow")):}

Answer»

Solution :From the slow step,
Rate `=k_(1)[NO_(3)][NO]`…………`(i)`
From fast step
EQULIBRIUM constant `(K)=([NO_(3)])/([NO][O_(2)])`…………`(II)`
Substituting the VALUE of `[NO_(3)]` from equation `(ii)` into equation `(i)`, we get
Rate `=k.[NO]^(2)[O_(2)]`


Discussion

No Comment Found

Related InterviewSolutions