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Nitrogen forms largest number of oxides in which oxidation state of nitrogen varies from +1 to +5 `N_(2)O,NO,N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5)` respectively. The largest number of oxides are formed due to capability of forming stable multiple bonds by nitrogen with oxygen. Q. Which of the following is/are correct statement(s)?A. In `N_(2)O_(4)` the N-N bond length is longer than the usual N-N single bond distanceB. `NO_(2)` molecule is angular and N-O bond length is intermediate between a single and a double bondC. `N_(2)O` is linear molecule and has small dipole momentD. All of these

Answer» Correct Answer - D


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