Nitrogen forms `N_(2)` but phosphorous when forms `P_(2)` gets readily converted into `P_(4)` becauseA. triple bond is present between phosphorus atomsB. `p pi -d pi ` bonding is weakC. `p pi- p pi` bonding is strongD. multiple bond is formed easily.

Nitrogen forms `N_(2)` but phosphorous when forms `P_(2)` gets readily

1.	Nitrogen forms `N_(2)` but phosphorous when forms `P_(2)` gets readily converted into `P_(4)` becauseA. triple bond is present between phosphorus atomsB. `p pi -d pi ` bonding is weakC. `p pi- p pi` bonding is strongD. multiple bond is formed easily.
Answer» Correct Answer - B `P_(2)` is unstable because the `p pi -d pi ` bonding in it is weak. It is due to larger atomic size of P and N. thus `P_(2)` is converted into `P_(4)` in which there is no `p pi -dpi` bonding.

Discussion

No Comment Found

Related InterviewSolutions

Which of the following species contains three bond pairs and one lone pair around the central atom?A. `BF_(3)`B. `NH H_(2)^(-)`C. `PCl_(3)`D. `H_(2)O`
Assertion : Between `SiCl_(4)` and `C Cl_(4)` only `SiCl_(4)` reacts with water. Reason : `SiCl_(4)` is ionic and `C Cl_(4)` is covalent.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true
Reaction of `HNO_(3)` with C,P,S and I respectively giveA. `HIO_(3),H_(2)SO_(4),H_(3)PO_(4)` and `CO_(2)`B. `HIO_(3),H_(2)SO_(4),H_(3)PO_(4)` and `CO_(2)`C. `I_(2)O_(5), H_(2)SO_(4),H_(3)PO_(3)` and COD. `I_(2)O_(5),SO_(2),P_(2)O_(5)` and `CO_(2)`
Assertion : `HNO_(3)` is a stronger acid than `HNO_(2)` Reason: In `HNO_(3)`, there are two nitrogen to oxygen bonds while in `HNO_(2)` there is only one.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true
Group 15 of the periodic table consists of the elements N, P, As, Sb and Bi. On passing from N to Bi, the oxides of the elements of general formula `M_2 O_3` becomeA. Stronger reducing agentsB. more ionicC. more basicD. more volatile
Which element from group 15 gives most basic compound with hydrogen?A. NitrogenB. BismuthC. AsenicD. Phosphorus
Which of the following is least basic?A. `NF_(3)`B. `NCl_(3)`C. `NBr_(3)`D. `NI_(3)`
Assertion : Among the hydrides of N-family , `NH_(3)` has highest boiling point . Reason: Extensive H-bonding is present in `NH_(3)` , while other elements of the group can not form H-bonding.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true
In the compounds of the type `POX_3`, P atoms show multiple bonding of the typeA. `p pi , dpi`B. `d pi, dpi `C. `p pi - dpi `D. no multiple bond is present
The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV

Nitrogen forms `N_(2)` but phosphorous when forms `P_(2)` gets readily converted into `P_(4)` becauseA. triple bond is present between phosphorus atomsB. `p pi -d pi ` bonding is weakC. `p pi- p pi` bonding is strongD. multiple bond is formed easily.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment