1.

Nitrogen tetraoxide (N_(2)O_(4)) decomposes as : N_(2) O_(4)(g) rarr 2NO_(2)(g) If the pressure of N_(2)O_(4) falls from 0.50 atm to 0.32 atm is 30 minutes the rate of appearance of NO_(2)(g) is :

Answer»

0.006 ATM `"min"^(-1)`
0.003 atm `"min"^(-1)`
0.012 atm `"min"^(-1)`
0.024 atm `"min"^(-1)`

Solution :Rate of disappearance of `N_(2)O_(4)`
`= (Delta[N_(2)O_(4)])/(Deltat)= (0.50-0.32)/(30)`
`= 0.006 atm min^(-1)`
Rate of APPEARANCE of `NO_(2)` = Twice rate of disappearance of `N_(2)O_(4)`
`2xx0.006 = 0.012 atm "min"^(-1)`


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