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No 8 The angles of a triangle are (x - 40) (x - 20) and(x/2- 10 )Find thevalue of x and the angles of the triangles.​

Answer»

Sum of angles of a triangle is 180°

the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5 

⇒ x = 100

Angles are:

x-40 = 100 - 40 = 60

x - 20 = 100 - 20 = 80

x/2 - 10 = 100/2 - 10 = 40

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