1.

No. of atoms in 4.25 g of NH3, is approx(1) 1 x 10^23(3) 2 x 10^23(2) 1.5 x 10^23(4) 6 × 10^23

Answer»

no of moles = 4.25/17 = 0.25 mol of NH3.1 mol of NH3 contains 6.022*10^23 molecules.0.25 mol NH3 contains 0.25*6.022*10^23 = 1.5055*10^23 molecules.1 molecule of NH3 contains 4 atoms.

Thanks



Discussion

No Comment Found