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| Answer» GIVEN :x^⅓ +y^⅓ +z^⅓= 0identity-if a+B+c = 0, then a³+b³+c³ = 3abcso,(x^⅓)³ + (y^⅓)³ + (c^⅓)³ = 3 (x^⅓× y^⅓ ×z^⅓)x+y+z = 3x^⅓ y^⅓ z^⅓option (b) | |