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Answer» N: -2 → +2 (a change of +4) (times 2 because there are 2N’s) Cl: +5→ -1 (a change of -6) Find the L.C.M. of change. 24 Insert the suitable stoichimetric coefficients: 3N2H4 + 4ClO3- → 6NO + 4Cl- Insert H2O to whichever side that is oxygen deficient and then insert H+ to whichever side that is hydrogen deficient: 3N2H4 + 4ClO3- → 6NO + 4Cl- +6H2O I have not understood...plz solve in easy way..by ion electron method. step by step. 1st page 2nd page 3rd page 4th page 5th page 6th page and last page what is your question? Go and ask this question to your teacher 👌 😎 |
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