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No til

Answer»

N: -2 → +2 (a change of +4) (times 2 because there are 2N’s)

Cl: +5→ -1 (a change of -6)

Find the L.C.M. of change.

24

Insert the suitable stoichimetric coefficients:

3N2H4 + 4ClO3- → 6NO + 4Cl-

Insert H2O to whichever side that is oxygen deficient and then insert H+ to whichever side that is hydrogen deficient:

3N2H4 + 4ClO3- → 6NO + 4Cl- +6H2O

I have not understood...plz solve in easy way..by ion electron method. step by step.

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