Saved Bookmarks
| 1. |
Non-stoichiometric cuprous oxide, Cu_(2)O can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2 : 1. Can you account for the fact that this substance is a p-type semiconductor ? |
| Answer» Solution :As the RATIO is less than `2: 1`, it INDICATES that some `CU^(+)` ions have been replaced by `Cu^(2+)` ions. For every two `Cu^(+)` ions displaced from the lattice site, one `Cu^(2+)` ion will be replaced to maintain ELECTRICAL neutrality. Thus, for every `Cu^(2+)` in the lattice, one HOLE will be created. These positive holes will be responsible for conduction of electricity. Hence, it is a p-type conductor. | |