1.

Normal aluminium electrodecoupled with normal hydrogen electrode gives an e.m.f. of 1.66 volts. So the standard electrode potential of aluminium is:-

Answer»

`-1.66V`
`+1.66V`
`-0.83V`
`+0.83V`

Solution :`E_(CELL)^(o)=1.66=E_(H^(+)//H_(2))^(o)-E_(AL^(3+)//Al)^(o)`
`=O-E_(Al^(3+)//Al)^(o)` or `E_(Al^(3+)//Al)=-1.66V`


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