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Note: Spam answer will be reported immidetly So no spamA surface with measures 80cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth. How many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases? |
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Answer» Total surface area of a suitcase = 2(lb + bh + HL) = 2(80 X 48 + 48 x 24 + 24 x 80) = 2(3840 + 1152 + 1920) cm2 = 2(6912) cm2 = 13824 cm2 ∴ Total S.A. of 100 suitcases = 100 x 13824 cm2 = 1382400 cm2 Surface area of 1 m of TARPAULIN = 100 cm x 96 cm = 9600 cm2 i.e. 1 m of tarpaulin can cover 9600 cm2 surface ∴ 1382400 over 9600 metres of tarpaulin will cover the total surfaces of 100 suitcases i.e. 1 m of tarpaulin can cover 9600 cm2 surface ∴ 1382400/9600 metres of tarpaulin will cover the total surfaces of 100 suitcases i.e. 1382400/9600 or 144 metres of tarpaulin will be required to cover 100 suitcases. |
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