^nPr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r)!}\)(d) \(\frac{n!}{(n-r)! r!}\)The question was posed to me by my college director while I was bunking the class.I would like to ask this question from Permutations-1 topic in chapter Permutations and Combinations of Mathematics – Class 11

^nPr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r

1.	^nPr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r)!}\)(d) \(\frac{n!}{(n-r)! r!}\)The question was posed to me by my college director while I was bunking the class.I would like to ask this question from Permutations-1 topic in chapter Permutations and Combinations of Mathematics – Class 11
Answer» CORRECT ANSWER is (C) \(\frac{n!}{(n-r)!}\) The best I can EXPLAIN: Permutation is known as arrangement. ^nPr MEANS arranging r objects out of n. ^nPr = \(\frac{n!}{(n-r)!}\).

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