1.

Nuclear reactor in which luranium-235 is used as fuel, uses 2 kg of uranium-235 in 30 days. Then power output of the reactor will be (given : Energy released per fission =185 MeV):

Answer»

43.5 MW
58.5 MW
69.6 MW
73.1 MW

Solution :NUMBER of ATOMS in 2KG of URANIUM
`=(6.02 xx 10^(23))/(235) xx 2000=5.12 xx 10^(24)`
Energy released `=5.12 xx 10^(24) xx 185MeV`
Time taken =30 days
Energy released per second
`= (5.12 xx 10^(24) xx 185 xx 1.6 xx 10^(-13))/(30 xx 24 xx 60 x 60)=58.47MW`


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