InterviewSolution
Saved Bookmarks
| 1. |
Nuclear reactor in which luranium-235 is used as fuel, uses 2 kg of uranium-235 in 30 days. Then power output of the reactor will be (given : Energy released per fission =185 MeV): |
|
Answer» 43.5 MW `=(6.02 xx 10^(23))/(235) xx 2000=5.12 xx 10^(24)` Energy released `=5.12 xx 10^(24) xx 185MeV` Time taken =30 days Energy released per second `= (5.12 xx 10^(24) xx 185 xx 1.6 xx 10^(-13))/(30 xx 24 xx 60 x 60)=58.47MW` |
|