1.

Nuclei of a radioactive element 'A' are being produced at a constant rate alpha the element has a decay constant lambda At time t=0 there are N_(0) nuclei of the element If alpha=2N_(0)lambdathe number of nuclei of A after t=(l n2)/lambda will become:

Answer»

ZERO
`2N_(0)`
`1.5 N_(0)`
`0.5 N_(0)`

ANSWER :C


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