1.

Nuclei of a radioactive element 'A' are being produced at a constant rate alpha the element has a decay constant lambda At time t=0 there are N_(0) nuclei of the element The number of nuclei of A at time 't' is

Answer»

`(ALPHA)/(lambda)(1-e^(-lambdat))`
`N_(0) e^(-lambdat)`
`1/(lambda)[alpha-(alpha- lambda N_(0))e^(-lambdat]`
`(N_(0).alpha)/lambda[1-((1-(lambda)/alpha))e^(-lambdat)]`

Answer :C


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