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Nuclei of radioactive element X. are being produced at a constant rute .K. and this element decays to a stable nucleus .Y. with decay constant .lamda. with half lite ..t_(0)... At time t=0, there are ..N.._(0).. number of nucle of the element .X. then The number N_(Y) of nuclei .Y. at time t=t_(0) is

Answer»

`K(LN2)/(lamda)+(3)/(2)((K-lamdaN_(0))/(lamda))`
`K(ln2)/(lamda)+(1)/(2)((K-lamdaN_(0))/(lamda))`
`K(ln2)/(lamda)-(1)/(2)((K-lamdaN_(0))/(lamda))`
`K(ln2)/(lamda)-2((K-lamdaN_(0))/(lamda))`

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