Nucleus ._(3)A^(7) has binding energy per nucleon of 10 MeV. It absorbs a proton and its mass increases by (90)/(100) times the mass of proton. Find the new binding energy of the nucleus so formed. [Take energy equivalent of proton = 930 MeV]

Nucleus ._(3)A^(7) has binding energy per nucleon of 10 MeV. It absorb

1.	Nucleus ._(3)A^(7) has binding energy per nucleon of 10 MeV. It absorbs a proton and its mass increases by (90)/(100) times the mass of proton. Find the new binding energy of the nucleus so formed. [Take energy equivalent of proton = 930 MeV]
Answer» Solution :`BE`=Original BINDING energy `+` Binding energy due to additional mass DEFECT `=70+(1)/(100)(930)=79.MeV`

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Nucleus ._(3)A^(7) has binding energy per nucleon of 10 MeV. It absorbs a proton and its mass increases by (90)/(100) times the mass of proton. Find the new binding energy of the nucleus so formed. [Take energy equivalent of proton = 930 MeV]

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