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Number of alpha- particles emitted per second by a radioactive element falls to 1//32 of its original value in 50 days. The half-life-period of this element is |
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Answer» 5 days `N = N_(0) xx ((1)/(2))^(n) or (1)/(32) = 1 xx ((1)/(2))^(n)`, or `((1)/(2))^(5) = ((1)/(2))^(n) or n = 5` `T = t_(1//2) xx 2, or t_(1//2) = (50)/(5) = 10` days. |
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