1.

Number of beta particles emitted during the decay of ""_(92)^(235) U to ""_(82)^(207)Pb

Answer»


Solution :`""_(92) U^(235) to ""_(82) Pb^(207) + a(""_(2) alpha^(4)) + b(""_(-1) beta^(0)) , a= ((235-206)/(4)) = 7 alpha`
`92 = 82 + (2 xx 7) - b , b = 14 + 82 - 92 = 14- 10 = 4 beta`


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