1.

Number of electrons liberated on cathode by passing 1 ampere current for 60 second during electrolysis is . . . .(Charge on electrone =1.60xx10^(-19)C)

Answer»

`3.75xx10^(20)`
`7.48xx10^(23)`
`6XX10^(23)`
`6xx10^(20)`

SOLUTION :`Q=n*E^(-)`
`Ixxt=n*e^(-)`
`n=(1xx60)/(1.6xx10^(-19))=3.75xx10^(20)e^(-)`


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