1.

Number of hydrogen ions present in 10 millionth part of 1.33 cm of pure water at 25°C is

Answer»

6.023 MILLION
60 million
8.01 million
80.23 million.

Solution :Now, `[H^(+)] = 10^(-7) mol//L`
Now, 1000 ML contains `10^(-7)` mole `H^(+)` ions
1 mL contains `10^(-7)/1000` mole `H^(+)`
`1.33 xx 10^(-7)` mL contains `1.33 xx 10^(-17)` mole `H^(+)` 10 million `=10^(-7)`
so, 10 million th part of 1.33 `cm^(3) = 1.33 xx 10^(-7)` mL
So, no. of `H^(+)` ions `=1.33 xx 10^(-17) xx N_(A)`


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