1.

Number of hydrogen ions present in 10 millionth part of 1.33 cm^(3) of pure water at 25^(@)C is

Answer»

6.023 million
60 million
8.01 million
80.23 million

Solution :Now `[H^(+)]=10^(-7)` mole/litre
Now 1000 ml CONTAINS `10^(-7)` mole `H^(+)`
1 ml contains `10^(-7)/1000` mole `H^(+)`
`1.33xx10^(-7)` ml - contains `1.33xx10^(-17)` 10 million `=10^(-7)` so, `10 "million"^(TH)` PART of `1.33 cm^(3)=1.33xx10^(-7)` ml
so, no. of `H^(+)` ions `=1.33xx10^(-17)xxN_(A)`.


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