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Number of integral values of 'a' for which (a-5)x^2 - 2ax + (a-4)=0 , has exactly one root in(0, 2), is |
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Answer» 18 ROOTS lies in the INTERVAL (0,2) f(2)=4a -20-4a+a-4=(a-24) f(0).f(2) lt 0 (a-4)(a-24) lt 0 a `in`(4,24 ) For a=4 `-x^2-8x=0` `x(x+8)=0 rArr r=0,-8` So a=4 is not possible For a=24 `19x^2 -48x +20=0` `19x^2 -38x -10x +20=0` (x-2)(19x-10)=0 `x=2,10/19` So , a =24 is possible so, a `in` (4,24) |
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