1.

Number of moles in 1 m^(3) gas at NTP are

Answer»

`4.46`
`44.6`
446
4460

Solution :`1M^(3)=10^(3)L=1000L`
`"1 MOLE = 22.4 L"`
`therefore" MOLES present in 1000 L"=(1000)/(22.4)=44.6`


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