InterviewSolution
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InterviewSolution
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Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will beA. 7.0 moleB. 0.2 moleC. 0.6 moleD. 0.4 mole |
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Answer» Correct Answer - D `[5e+MnO_(4)^(-)+8H^(+)rarrMn^(2+)+4H_(2)O…(i)]xx2` `[C_(2)O_(4)^(2-)rarr 2e+2CO_(2)…(ii)]xx5` `MnO_(4)^(-)+16H^(+)+5C_(@)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)` As 2 moles of `MnO_(4)^(-)` required to oxidize 5 moles of oxalate. So number of moles of `MnO_(4)^(-)` required to oxidize 1 mole of oxalate = 2/5=0.4. |
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