1.

Number of moles of [NH_4OH] required to coagulate 1mole of [Fe(OH)_3]Fe^(+3) are

Answer»

3 
4 
2
1

Solution :`3NH_4OH + [FE(OH)_3]Fe^(+3) to Fe(OH)_3`
MOLES of `NH_4OH` required to COAGULATE `[Fe(OH)_] Fe^(+3)` ion = 3


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