Number of neutrons in a parent nucleus X, which given ._(7)N^(14) nucl – InterviewSolution

1.	Number of neutrons in a parent nucleus X, which given ._(7)N^(14) nucleus after two successive beta emission would be
Answer» 9 8 7 6 Solution :`._(5)X^(14) OVERSET(-2beta)rarr ._(7)N^(14)` then no. of NEUTRONS in `._(5)X^(14) = 14 - 5 = 9`

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