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NUMERICAL QUESTIONS A person throws a ball straight up with a speed of 12 m/s. If the bus ismoving at 25 m/s, what is the velocity of the ball to an observer onground?(V2 = 28 m/s, OR = 26°)or at an angle of 54° nositive X-​

Answer»

If a ball is THROWN straight up with a speed of 12 m/s, it will begin accelerating at -9.8 m/s^2 in the vertical axis and the vertical velocity will immediately begin to decrease. If this question is asking about the velocity of the ball at the instant that it was released, then this can be calculated, otherwise the vertical velocity is unknown without a specific period of time after the throw being given.The vertical velocity is 12 m/s initially and the initial horizontal velocity of the ball is the same as the bus, 25 m/s. Air resistance being NEGLIGIBLE should be stated in this question. To add these two velocity components together, SINCE they are perpendicular vectors, the Pythagorean Theorem can be used to calculate the MAGNITUDE of the velocity of the ball. Then this right triangle can be used with trigonometry to determine the angle of the initial velocity, which is necessary for the answer to be the velocity.


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