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O is the centre, ∠AOB = 120°, find ∠BAC. Captionless Image​

Answer»

-step explanation:ABCD is a CYCLIC quadrilateral. we have ∠ABC+∠ADC=180 o ∠ABC=180 o −120 o =60 o Also ∠ACB=90 o ( ANGLE on a SEMI circle ) In ΔABC we have ∠BAC+∠ACB+∠ABC=180 o ∠BAC+90 o +60 o =180 o ∠BAC=180 o −150 o =30 o Answer



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