O is the centre of a circle of radius 6 cm. P is the point such that AP = 10 cm and OP intersects the circle at T and PC, PD are two tangents drawn to the circle. if AB is the tangent to the circle at T find the length AB.

O is the centre of a circle of radius 6 cm. P is the point such that A

1.	O is the centre of a circle of radius 6 cm. P is the point such that AP = 10 cm and OP intersects the circle at T and PC, PD are two tangents drawn to the circle. if AB is the tangent to the circle at T find the length AB.
Answer» -step explanation:Let O be the centre of the given circle and let P be a POINT such that OP = 10 CM.Let PT be the tangent such that PT = 8 cm.Join OT.Now, PT is a tangent at T and OT is the radius through T.Therefore, OT⊥PT.Using pythagoras theorem in △OTP, we have,OP 2 =OT 2 +PT 2 OT 2 =100−64=36OT=6 cmTherefore, the radius of the circle is 6 cm.

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O is the centre of a circle of radius 6 cm. P is the point such that AP = 10 cm and OP intersects the circle at T and PC, PD are two tangents drawn to the circle. if AB is the tangent to the circle at T find the length AB.​

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O is the centre of a circle of radius 6 cm. P is the point such that AP = 10 cm and OP intersects the circle at T and PC, PD are two tangents drawn to the circle. if AB is the tangent to the circle at T find the length AB.