O is the centre of the circle whose radius is 41 CM. The length of the

1.	O is the centre of the circle whose radius is 41 CM. The length of the chord PQ of the circle is 80 cm. Find the distance of the chord from the centre O.
Answer» PO^2 = OM^2 + PM^2 ( hypothenus) PM Is HALF of PQ PM = 80 / 2 PM = 40 cm OM Is radius = 41 cm PO^2 =(41 × 41) + (40 × 40) PO^2 = 1681+1600 PO^2 = 3281cm^2 PO = √3281 PO = 57.28cm

O is the centre of the circle whose radius is 41 CM. The length of the chord PQ of the circle is 80 cm. Find the distance of the chord from the centre O.

Answer»

PO^2 = OM^2 + PM^2 ( hypothenus)

PM Is HALF of PQ

PM = 80 / 2

PM = 40 cm

OM Is radius = 41 cm

PO^2 =(41 × 41) + (40 × 40)

PO^2 = 1681+1600

PO^2 = 3281cm^2

PO = √3281

PO = 57.28cm