1.

OACB is a parallelogram with bar(OC)=bar(a), bar(AB)=bar(b)" then "bar(OA)=

Answer»

`(BAR(a)+bar(B))/2`
`bar(a)+bar(b)`
`(bar(a)-bar(b))/2`
`bar(a)-bar(b)`

ANSWER :C


Discussion

No Comment Found