1.

Object of 100 g mass moves with velocity of 36 km/hr .de-Broglie wavelength associated with it will be of ………order (h=6.626xx10^(-34)Js)

Answer»

`10^(-14)`
`10^(-34)`
`10^(-24)`
`10^(-44)`

Solution :v=36 km/hr
`=(36xx1000)/(3600)(m)/(s)=10(m)/(s)`
de-Broglie WAVELENGTH ,
`lambda=(h)/(p)=(h)/(mv)=(6.626xx10^(-34))/(0.1xx10)`
`lambda=6.626xx10^(-34)m`
`therefore 10^(-34)m` ORDER


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