1.

Object of small length 1 is placed on the axis of concave mirror of focal length f, then size of image will be ...... if object is at distance d from pole.

Answer»

`(If)/(d-F)`
`(d-f)/(If)`
`L(f^2)/((d-f)^2)`
`((d-f)^2)/(f^2).l`

Solution :By USING `1/v+1/u=1/f`
when u=d+1
Image size=`v_1-v_2=l((f)/(d-f))^2`


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