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Objective3, A linear harmonic oscillator of force constant 2 × 106 NmQuestionII(Oneormorecorrectoptionand amplitude 0.01m has a total mechanical energy of160 J. Its(a) maximum potential energy is 100 J(b) maximum kinetic energy is 100 J(c) maximum potential energy is 160 J(d) maximum potential energy is zero(1989,2M |
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Answer» We know that maximum potential energy=total mechanical energy. Thus, maximum P.E.=160J. For calculating the maximum kinetic energy, the formula used is max K.E.=1/2*k*a^2. (and not the usual 1/2*k(a^2-x^2) So, maximum K.E.=1/2*2x10^6*(0.01^2) which is equal to 100J. |
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