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Objective3, A linear harmonic oscillator of force constant 2 × 106 NmQuestionII(Oneormorecorrectoptionand amplitude 0.01m has a total mechanical energy of160 J. Its(a) maximum potential energy is 100 J(b) maximum kinetic energy is 100 J(c) maximum potential energy is 160 J(d) maximum potential energy is zero(1989,2M

Answer»

We know that maximum potential energy=total mechanical energy.

Thus, maximum P.E.=160J.

For calculating the maximum kinetic energy, the formula used is max K.E.=1/2*k*a^2. (and not the usual 1/2*k(a^2-x^2)

So, maximum K.E.=1/2*2x10^6*(0.01^2) which is equal to 100J.



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