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Observe the figure showing the path of a body which started from A and moved to C through B.B60 m40m4s6s70ma.C.Calculate the speed of the body.b. What is the velocity of the body?What is the velocity of the body if it has taken 5 s to reachA back from C?d. Compare the velocity of the body when it reached fromA and also when it reached A from C.? |
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Answer» Magnitude of AREA under the v−t graph GIVES the distance travelled by the body. For 0≤t≤4 s : Displacement S 1 = Area = 2 1 ×(20+40)×2+ 2 1 ×(1+2)×20=90 m For 4≤t≤5 s : Displacement S 2 = Area = 2 1 ×1×20=10 m TOTAL distance d=S 1 +S 2 =90+10=100 m OPTION A is correct. |
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