1.

Observe the figure showing the path of a body which started from A and moved to C through B.B60 m40m4s6s70ma.C.Calculate the speed of the body.b. What is the velocity of the body?What is the velocity of the body if it has taken 5 s to reachA back from C?d. Compare the velocity of the body when it reached fromA and also when it reached A from C.?​

Answer»

Magnitude of AREA under the v−t graph GIVES the distance travelled by the body. For  0≤t≤4 s : Displacement  S  1 ​   = Area =  2 1 ​   ×(20+40)×2+  2 1 ​   ×(1+2)×20=90 m For  4≤t≤5 s : Displacement  S  2 ​   = Area =  2 1 ​   ×1×20=10 m TOTAL distance d=S  1 ​   +S  2 ​   =90+10=100 m OPTION A is correct.



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