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Obtain an expression for effective Capacitance of two Capacitors Connected in series. |
Answer» Solution : ` V = V_1 + V_2` ` V = (Q)/(C_1)` and `V_2 = (Q)/(C_2)` and susbtituting to GET`V = Q =[ (1)/(C_1) +(1)/(C_2)]` ` RARR (1)/(C_5)= (1)/(C_1) + (1)/(C_2)` |
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