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Obtain an expression for half-life period of zero order reaction. |
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Answer» Solution :The rate LAW expression for zero order reactio'n is,`[A]_(t) = -kt [A]_(0)` Where `[A]_(0)`and `[A]_(0)`are theconcentrationof thereactantat time t - 0 andaftertime t respectively. Half -lifeperiod`t_(1//2)`is the time WHENTHE CONCETRATION reduce form `[A]_(0)`to `[A]_(0)` /2. .E., at `t = t_(1//2)` `[A]_(t) = [A]_(0)`/2. `therefore([A]_(0))/(2) = - kt_(1//2) +[A]_(0)` ` therefore kt_(1//2) = ([A]_(0))/(2) = ([A]_(0))/(2)` `therefore t_(1//2) = ([A]_(0))/(2k)` Hence for a zero order reaction, half-life PERIOD 1s directlyproportional to the initial concentration of the reactant. |
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