Saved Bookmarks
| 1. |
Obtain an expression for magnetic Lorentz force? |
|
Answer» Solution :When an electric CHARGE q is moving with VELOCITY `vecv` in the magnetic field `vecB`, it EXPERIENCES a force , called magnetic force `vecF_(m) `. Aftercareful experiments , Lorentz deduced the force experienced by a moving charge in the magnetic field `vecF_(m) `. `vecF_(m) = q (vecv xx vecB)` ....(1) In magnitude , `F_(m)= q v B sin theta` .....(2) The equations (1) and equation (2) imply 1. `vecF_(m) ` is directly proportional to the magnetic field `vecB` 2. `vecF_(m) ` is directly proportional to the velocity `vecv` 3. `vecF_(m) ` is directly proportional to sine of the ANGLE between the velocity and magnetic field 4. `vecF_(m) `is directlyproportional to the magnitude of the charge q 5. The direction of `vecF_(m) ` isalways perpendicular to `vecv " and " vecB " as " vecF_(m) ` in the cross product of `vecv " and " vecB`  7. The direction of `vecF_(m) ` on negative charge is opposite to the direction of `vecF_(m) ` on positive charge provided other factors are identical as shown Figure. 8. If velocity `vecv ` of the charge q is along magnetic field `vecB " then, " vecF_(m) ` is zero. |
|