Saved Bookmarks
| 1. |
Obtain an expression for the frequency of radiation emitted when a hydrogen atom de-exites from level n to level (n-1) . For large n, show that frequency equals the classicalfrequency of revolution of the electron in the orbit. |
|
Answer» Solution :The energy of an ELECTRON in the N -th energy level of hydrogen atom `E_n =(-2pi^2me^4)/((4pi in_0)^2*n^2h^2)` `therefore E_n-E_(n-1)=(2pi^2me^4)/((4piin_0)^2*h^2)*(2n-1)/(n^2(n-1)^2)` `therefore` FREQUENCY, f `=(E_n-E_(n-1))/(h) =(2pi^2me^4)/((4piin_0)^2h^3) *(2n-1)/(n^2(n-1)^2)` |
|