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Obtain approximately the ratio of the nuclear radii of the gold isotope ""_(79)^(197)Au and the silver isotope ""_(47)^(107)Ag. |
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Answer» SOLUTION :`R = R_0 A^(1//3)` For `""_(79)^(197)AU, R_(Au) = R_0 (197)^(1//3) , "For " ""_(47)^(107)AG, R_(Ag) = R_0 (107)^(1//3)` `(R_(Au))/(R_(Ag)) = (197/107)^(1//3) = 1.23`. |
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