Saved Bookmarks
| 1. |
Obtain approximately the ratio of the nuclear radii of the gold isotope " "_(79^(197)Au and the silver isotope " "_(47)^(107)Ag. |
|
Answer» Solution :We KNOW that nuclear RADIUS is given by R=`R_(0) (A)^(1/3)` `therefore (R(" "_(79)^(197)AU))/(R(" "_(47)^(107)Ag))=(197/107)^(1/3)=1.23`. |
|