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Obtain Gauss's law from Coulomb's law. |
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Answer» SOLUTION :Coulombian force acting between charges Q +q is, `F = 1/(4PI epsilon_(0)).(Qq)/r^(2)` `F/Q =q/(4pi epsilon_(0).r^(2))` But, `F/Q =vecE` [Force acting on Q charge placed in ELECTRIC FIELD of q means intensity of electric field E] `THEREFORE E = 1/(4pi epsilon_(0)).q/r^(2)` `therefore E xx 4pir^(2) =q/epsilon_(0)` `therefore intEds = q/epsilon_(0)`, where `4pir^(2) = ds` As E and ds are vectors. `intvecE.vec(ds) =q/epsilon_(0)`. This is Gauss.s law. |
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