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Obtain the binding energy (in MeV) of a nitrogen nucleus (""_7^14 N), given m (""_7^14N) = 14.00307 u . |
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Answer» Solution :`BE = [{Zm_P + (A -Z)m_N}-M]c^2` BINDING ENERGY of `""_7^14N = [{7 xx 1.007825 + 7 xx 1.008665} - 14.00307] 931( :. 1U = 931 (MeV)/(c^2))` `= 104.61 MeV`. |
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