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Obtain the de Broglie wavelengthassociated with thermal neutron at roon temperature30^(@)C. |
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Answer» Solution :`T=273+30=303K, k=1.38xx10^(-23)` Thermal neutrons kinetic theory of gases. `therefore` Kinetic ENERGY of a thermal neutron is given by, `K=(3)/(2)kT=(3)/(2)xx1.38xx10^(-23)xx303=0.627xx10^(-20)J` `lambda=(h)/(SQRT(2mK))=(6.625xx10^(-34))/(sqrt(2xx1.67xx10^(-27)xx0.627xx10^(-20)))=1.45xx10^(-10)m` |
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