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Obtain the expression of electric field at any point by continuous distribution of charge on a line. |
Answer» SOLUTION :Suppose, line is divided into smaller elements of dl length and `VECR`is the POSITION vector of any smaller element and its linear charge density is `lambda`and its charge is `lambdadl`.  Suppose a point P (inside or outside) WHOSE, position vector is `vecR`. P is at `r.`distance from Al element and unit vector is `vecr`. Electric field at P due to `lambdaDeltal` `vec(DeltaE) = (klambda Deltal)/(r.)^(2).hatr` Total electric field at P by superposition principle. `vecE = sum_(Deltal) (klambdaDeltal)/(r.)^(2).r` By integration method. `vecE = int_(l) (klambdadl)/(r.)^(2).hatr` |
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