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Obtain the expression of electric field by thin spherical shell with uniform charge distribution at a point inside it. |
Answer» Solution :As shown in FIGURE, surface charge density on spherical SHELL of radius R is `sigma`  The point P is inside the shell. The Gaussian surface is a SPHERE through P centered at O of radius r. The FLUX through the Gaussian surface, calculated as before is `E xx 4pir^(2)`. In this case, the Gaussian surface encloses no charge. Gauss.s law gives, `E xx 4pir^(2) =0 , (therefore q/epsilon_(0) =0 "as" q=0)` `therefore E =0, (r LT R)` Thus, the field due to a uniformly charged thin shell is zero at all points inside the shell. |
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