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Obtain the mass of an electron in hydrogen atom in terms of its orbital period and radius of orbit. |
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Answer» Solution :The required centripetal FORCE of the electron in the hydrogen ATOM is provided by the coulomb force, `:. (mv^(2))/(r)=(1)/(4PI epsi_(0))(e^(2))/(r^(2))(Z=1)` `:.(mr^(2) omega^(2))/(r)=(1)/(4pi epsi_(0)) (e^(2))/(r^(2)) ( :. v=romega)` `:. m omega^(2)=(1)/(4pi epsi_(0))(e^(2))/(r^(3))` Here TAKING `omega=(2pi)/(T)`, `:.m((4pi^(2))/(T^(2)))=(1)/(4pi epsi_(0))(e^(2))/(r^(3))` `:.m=(e^(2)T^(2))/(16pi^(3)epsi_(0)r^(3))` |
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